| obviously have to look at what the engine is doing through the RPM band that you are driving the car at. On average, the tranny in the 5spd Z has about 1500RPM intervals between shifts if you shift at around 6500RPM. In this case, you will have to look solely at that RPM band and make the determination. Taking both HP and torque into consideration through that band will tell you how the car is going to move down the track. The approach you have to take in this is to assume that you will always have 100% traction (as we are only trying to determine the work that can be done by a given HP and TQ through the used powerband). While you dont always have 100% traction, we can neglect that for now as that is a whole can or worms for another discussion. :) Since the HP is constrained to torque as well as RPM, it sets the playing field as equal in terms of RPM. Clarifying that, if you compare a rortary to a 6 cylinder, the rotary will obviously be working in a higher RPM band. One problem with trying to apply this in an empirical test is determining what sets both equal; i.e. should you run two cars down the track that have the same HP or the same TQ through the RPM bands used to make the determination. It wouldn't be a race to see who could get there the fastest so you could take two cars with the boost turned down (and again, you would have to make them equal in both HP for a run, then also equal in TQ for another run), but by doing this, you wont have to take traction into account. It is simply a test to see which one would get down to the end first, and even plotting distance vs. time and velocity vs. distance to see the relationship of how the vehicles progress down the track. But again, I would think there is a much easier explanation to this question; one which can be solved mathematically. Admittedly, it is as little over my head.
[ ashleypowers.com ]
[ agpowers@bellsouth.net ] [ Zemulator Information Sheet ] Enthusiasts soon understand each other. --W. Irving.
Are you an enthusiast?
|
