| :You are confused. Physics says that you can't get more energy recombining the O2 and H2 to get H20 than you put into splitting them. The process described is much different from simple recombination of O2 and H2. I see that we agree about the basics here regarding the physics behind this, but I fail to see how this differs any from what I am saying. I know that he's not burning 100% water here. But my point of contention is that electrolyzing ANY water at all and burning the byproducts will results in a slight loss of net power. The more you electolyze/burn, the more power that is consumed. This is because this is a power-robbing process. So the fact that this is only supposed to "support" combustion doesn't change the physics involved. Just its introduction will sap some power from the overall system.
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