| For giggles. The moment of inertia is : I = (1/2) m r^2 for a simple disk h=0 Say mass is 20lbs Say radius is .8ft or a diameter of 20 inches (not sure exact dimensions of a TT flywheel) I = .5*20lb * (.8ft)^2 = 6.4lbft^2 Now say mass is 12lbs Same radius I = .5*12lbs * (.8ft)^2 = 3.8lbft^2 A difference of 2.6lbft^2 Now plug the difference into the the angular momentum equation L = Iw Assume w at 2000 rpm and lets see what change in angular momentum we have. L=(2.6lbft^2)(2000rpm)(2pi/1rev)(1/60s) = 544 lbft^2/s
That's a considerable difference in the change in angular momentum, which is fair to say that people can probably feel the difference in engine response.
|