| If we are using a shift as an example here, a close and open of the throttle, then I think your explanation is missing something. As the pressure gradient builds in the system, the air is in fact moving. As the TBs close and the BOVs open, the pressure is being released. Now, going with your theory, if the BOVs are on the IC pipes, the pressure zone gets halted at the TB, and then reverts back to the valve. "A BOV on the intercooler pipes would cause reversion in the system, and vent pressure from both sides of the pressure gradient. Thus the turbo will have to fight the kinetic forces of reverted intake gas upon throttle reopening." So the pressure has to move backwards from the TB to be vented, so to speak. The portion of the pressure gradient that is in front of the valve, yes. But don't you think that as the throttle reopens, the air would go automatically to that new area of least resistance? Yes, but there is still a pressurized column of air ahead of the valve. Especially given the vaccum that the motor operates under before the turbo creates positive manifold pressure? The pressurized column of air is more than the engine vacuum can consume before it would reverse directions and heads towards the BOV to be vented. So it seems that the turbo would not have to overcome the reversion as the BOV has vented most of it (before it reaches the turbo) and now that the TB is open, the motor is now drawing that air in. It would never reach the turbo of course. It's similar to hacking open a pipe in your plumbing system between two water towers. The water would flow from reservoirs out of to the area of low pressure, but would not flow from the top of one tower to the top of the other. In other words, the turbo doesn't see the reversion because the BOV is there, given of course the BOV can flow the volume required to release the pressure. This would imply that the location is of little consequence. Given that the BOV completely depressurizes the entire intake tract once open, the remaining molecules of air flowing in reverse would probably be negligible. If it doesn't completely depressurize the system, the remaining kinetic energy to overcome wouldn't be negligible. There are about 20 "ifs" in this conversation, and any one could really decide the case. Your point has merit. That being said, I'm right and you're wrong. Mostly because I'm using bold text.
Recursively Yours,
Kenny...
PETZ Member #5
SteamyZ. Never had did me wrong. - SL103 07/06/04 11:58:15
|
