torque applied to the drums. If your engine produces 300ft. lbs of torque. You have a final ratio of 3:1 that means you have 900 ft.lbs of torque applied to the drums. I'm speaking theoritical barring frictional loses. The dyno jet calculates the HP from the spinning of the drums. Now we know the HP. We get the tach RPM signal and get the engine torque values for the HP delivered at that moment in time. If you change gear ratios, your torque changes on the drum but your HP doesn't change. You are still doing the same amount work. Lower gear gives more torque less rpm vs. higher gear gives less torque and more rpm.
If the HP was 300 the dyno jet measured @ 5000 rpm. What was the torque? Solve for torque by plugging in the variables 300HP = (5000 x torque)/ 5252 . There is no gear ratio in the equation.
10:49:16 08/10/04
